9+3/5z=12

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Solution for 9+3/5z=12 equation: 



9+3/5z=12

We move all terms to the left:

9+3/5z-(12)=0



Domain of the equation: 5z!=0

z!=0/5

z!=0

z∈R



We add all the numbers together, and all the variables

3/5z-3=0

We multiply all the terms by the denominator


-3*5z+3=0

Wy multiply elements

-15z+3=0

We move all terms containing z to the left, all other terms to the right

-15z=-3

z=-3/-15

z=1/5

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