9+3b+(2b-2)=67

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Solution for 9+3b+(2b-2)=67 equation:



9+3b+(2b-2)=67
We move all terms to the left:
9+3b+(2b-2)-(67)=0
We add all the numbers together, and all the variables
3b+(2b-2)-58=0
We get rid of parentheses
3b+2b-2-58=0
We add all the numbers together, and all the variables
5b-60=0
We move all terms containing b to the left, all other terms to the right
5b=60
b=60/5
b=12

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