9+3b+2(b-1)=68

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Solution for 9+3b+2(b-1)=68 equation: 



9+3b+2(b-1)=68

We move all terms to the left:

9+3b+2(b-1)-(68)=0

We add all the numbers together, and all the variables

3b+2(b-1)-59=0

We multiply parentheses

3b+2b-2-59=0

We add all the numbers together, and all the variables

5b-61=0

We move all terms containing b to the left, all other terms to the right

5b=61

b=61/5

b=12+1/5

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