9+3b=2(b-1)=67

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Solution for 9+3b=2(b-1)=67 equation: 



9+3b=2(b-1)=67

We move all terms to the left:

9+3b-(2(b-1))=0



We calculate terms in parentheses: -(2(b-1)), so:

2(b-1)

We multiply parentheses

2b-2

Back to the equation:

-(2b-2)



We get rid of parentheses

3b-2b+2+9=0

We add all the numbers together, and all the variables

b+11=0

We move all terms containing b to the left, all other terms to the right

b=-11

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