9+3x(3x+4)=5

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Solution for 9+3x(3x+4)=5 equation: 



9+3x(3x+4)=5

We move all terms to the left:

9+3x(3x+4)-(5)=0

We add all the numbers together, and all the variables

3x(3x+4)+4=0

We multiply parentheses

9x^2+12x+4=0

a = 9; b = 12; c = +4;
Δ = b2-4ac
Δ = 122-4·9·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{18}=-2/3$

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