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9+3x(3x+4)=5
We move all terms to the left:
9+3x(3x+4)-(5)=0
We add all the numbers together, and all the variables
3x(3x+4)+4=0
We multiply parentheses
9x^2+12x+4=0
a = 9; b = 12; c = +4;
Δ = b2-4ac
Δ = 122-4·9·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-12}{18}=-2/3$
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