9+3x+(2x-2)=67

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Solution for 9+3x+(2x-2)=67 equation: 



9+3x+(2x-2)=67

We move all terms to the left:

9+3x+(2x-2)-(67)=0

We add all the numbers together, and all the variables

3x+(2x-2)-58=0

We get rid of parentheses

3x+2x-2-58=0

We add all the numbers together, and all the variables

5x-60=0

We move all terms containing x to the left, all other terms to the right

5x=60

x=60/5

x=12

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