9+4(2y-2)=-5(3y-2)+8y

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Solution for 9+4(2y-2)=-5(3y-2)+8y equation: 



9+4(2y-2)=-5(3y-2)+8y

We move all terms to the left:

9+4(2y-2)-(-5(3y-2)+8y)=0

We multiply parentheses

8y-(-5(3y-2)+8y)-8+9=0



We calculate terms in parentheses: -(-5(3y-2)+8y), so:

-5(3y-2)+8y

We add all the numbers together, and all the variables

8y-5(3y-2)

We multiply parentheses

8y-15y+10

We add all the numbers together, and all the variables

-7y+10

Back to the equation:

-(-7y+10)



We add all the numbers together, and all the variables

8y-(-7y+10)+1=0

We get rid of parentheses

8y+7y-10+1=0

We add all the numbers together, and all the variables

15y-9=0

We move all terms containing y to the left, all other terms to the right

15y=9

y=9/15

y=3/5

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