9+4(5y-5)=-2(3y-2)+8y

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Solution for 9+4(5y-5)=-2(3y-2)+8y equation: 



9+4(5y-5)=-2(3y-2)+8y

We move all terms to the left:

9+4(5y-5)-(-2(3y-2)+8y)=0

We multiply parentheses

20y-(-2(3y-2)+8y)-20+9=0



We calculate terms in parentheses: -(-2(3y-2)+8y), so:

-2(3y-2)+8y

We add all the numbers together, and all the variables

8y-2(3y-2)

We multiply parentheses

8y-6y+4

We add all the numbers together, and all the variables

2y+4

Back to the equation:

-(2y+4)



We add all the numbers together, and all the variables

20y-(2y+4)-11=0

We get rid of parentheses

20y-2y-4-11=0

We add all the numbers together, and all the variables

18y-15=0

We move all terms containing y to the left, all other terms to the right

18y=15

y=15/18

y=5/6

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