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9+4n=1/2n-1
We move all terms to the left:
9+4n-(1/2n-1)=0
Domain of the equation: 2n-1)!=0We get rid of parentheses
n∈R
4n-1/2n+1+9=0
We multiply all the terms by the denominator
4n*2n+1*2n+9*2n-1=0
Wy multiply elements
8n^2+2n+18n-1=0
We add all the numbers together, and all the variables
8n^2+20n-1=0
a = 8; b = 20; c = -1;
Δ = b2-4ac
Δ = 202-4·8·(-1)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-12\sqrt{3}}{2*8}=\frac{-20-12\sqrt{3}}{16} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+12\sqrt{3}}{2*8}=\frac{-20+12\sqrt{3}}{16} $
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