9+5(3y-1)=-2(4y-4)+7y

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Solution for 9+5(3y-1)=-2(4y-4)+7y equation: 



9+5(3y-1)=-2(4y-4)+7y

We move all terms to the left:

9+5(3y-1)-(-2(4y-4)+7y)=0

We multiply parentheses

15y-(-2(4y-4)+7y)-5+9=0



We calculate terms in parentheses: -(-2(4y-4)+7y), so:

-2(4y-4)+7y

We add all the numbers together, and all the variables

7y-2(4y-4)

We multiply parentheses

7y-8y+8

We add all the numbers together, and all the variables

-1y+8

Back to the equation:

-(-1y+8)



We add all the numbers together, and all the variables

15y-(-1y+8)+4=0

We get rid of parentheses

15y+1y-8+4=0

We add all the numbers together, and all the variables

16y-4=0

We move all terms containing y to the left, all other terms to the right

16y=4

y=4/16

y=1/4

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