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9+5x=1+2(x+4)
We move all terms to the left:
9+5x-(1+2(x+4))=0
We calculate terms in parentheses: -(1+2(x+4)), so:We get rid of parentheses
1+2(x+4)
determiningTheFunctionDomain 2(x+4)+1
We multiply parentheses
2x+8+1
We add all the numbers together, and all the variables
2x+9
Back to the equation:
-(2x+9)
5x-2x-9+9=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0
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