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9-(2-3x)=6+2x-(6+x)
We move all terms to the left:
9-(2-3x)-(6+2x-(6+x))=0
We add all the numbers together, and all the variables
-(-3x+2)-(6+2x-(x+6))+9=0
We get rid of parentheses
3x-(6+2x-(x+6))-2+9=0
We calculate terms in parentheses: -(6+2x-(x+6)), so:We add all the numbers together, and all the variables
6+2x-(x+6)
determiningTheFunctionDomain 2x-(x+6)+6
We get rid of parentheses
2x-x-6+6
We add all the numbers together, and all the variables
x
Back to the equation:
-(x)
2x+7=0
We move all terms containing x to the left, all other terms to the right
2x=-7
x=-7/2
x=-3+1/2
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