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9-(2/5k)=1
We move all terms to the left:
9-(2/5k)-(1)=0
Domain of the equation: 5k)!=0We add all the numbers together, and all the variables
k!=0/1
k!=0
k∈R
-(+2/5k)+9-1=0
We add all the numbers together, and all the variables
-(+2/5k)+8=0
We get rid of parentheses
-2/5k+8=0
We multiply all the terms by the denominator
8*5k-2=0
Wy multiply elements
40k-2=0
We move all terms containing k to the left, all other terms to the right
40k=2
k=2/40
k=1/20
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