9-(3c+1)=-0.5(2c+12)

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Solution for 9-(3c+1)=-0.5(2c+12) equation: 



9-(3c+1)=-0.5(2c+12)

We move all terms to the left:

9-(3c+1)-(-0.5(2c+12))=0

We get rid of parentheses

-3c-(-0.5(2c+12))-1+9=0



We calculate terms in parentheses: -(-0.5(2c+12)), so:

-0.5(2c+12)

We multiply parentheses

-c-6

We add all the numbers together, and all the variables

-1c-6

Back to the equation:

-(-1c-6)



We add all the numbers together, and all the variables

-3c-(-1c-6)+8=0

We get rid of parentheses

-3c+1c+6+8=0

We add all the numbers together, and all the variables

-2c+14=0

We move all terms containing c to the left, all other terms to the right

-2c=-14

c=-14/-2

c=+7

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