9-(4x-18)=(36+4x)+(18-6x)

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Solution for 9-(4x-18)=(36+4x)+(18-6x) equation: 



9-(4x-18)=(36+4x)+(18-6x)

We move all terms to the left:

9-(4x-18)-((36+4x)+(18-6x))=0

We add all the numbers together, and all the variables

-(4x-18)-((4x+36)+(-6x+18))+9=0

We get rid of parentheses

-4x-((4x+36)+(-6x+18))+18+9=0



We calculate terms in parentheses: -((4x+36)+(-6x+18)), so:

(4x+36)+(-6x+18)

We get rid of parentheses

4x-6x+36+18

We add all the numbers together, and all the variables

-2x+54

Back to the equation:

-(-2x+54)



We add all the numbers together, and all the variables

-4x-(-2x+54)+27=0

We get rid of parentheses

-4x+2x-54+27=0

We add all the numbers together, and all the variables

-2x-27=0

We move all terms containing x to the left, all other terms to the right

-2x=27

x=27/-2

x=-13+1/2

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