9-(t+1)=4+2(t+3)

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Solution for 9-(t+1)=4+2(t+3) equation: 



9-(t+1)=4+2(t+3)

We move all terms to the left:

9-(t+1)-(4+2(t+3))=0

We get rid of parentheses

-t-(4+2(t+3))-1+9=0



We calculate terms in parentheses: -(4+2(t+3)), so:

4+2(t+3)

determiningTheFunctionDomain
2(t+3)+4

We multiply parentheses

2t+6+4

We add all the numbers together, and all the variables

2t+10

Back to the equation:

-(2t+10)



We add all the numbers together, and all the variables

-1t-(2t+10)+8=0

We get rid of parentheses

-1t-2t-10+8=0

We add all the numbers together, and all the variables

-3t-2=0

We move all terms containing t to the left, all other terms to the right

-3t=2

t=2/-3

t=-2/3

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