9-(x+4)=2(x-3)+12

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Solution for 9-(x+4)=2(x-3)+12 equation: 



9-(x+4)=2(x-3)+12

We move all terms to the left:

9-(x+4)-(2(x-3)+12)=0

We get rid of parentheses

-x-(2(x-3)+12)-4+9=0



We calculate terms in parentheses: -(2(x-3)+12), so:

2(x-3)+12

We multiply parentheses

2x-6+12

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

-1x-(2x+6)+5=0

We get rid of parentheses

-1x-2x-6+5=0

We add all the numbers together, and all the variables

-3x-1=0

We move all terms containing x to the left, all other terms to the right

-3x=1

x=1/-3

x=-1/3

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