9-1(1-3y)=4+y-(3-y)

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Solution for 9-1(1-3y)=4+y-(3-y) equation: 



9-1(1-3y)=4+y-(3-y)

We move all terms to the left:

9-1(1-3y)-(4+y-(3-y))=0

We add all the numbers together, and all the variables

-1(-3y+1)-(4+y-(-1y+3))+9=0



We calculate terms in parentheses: -(4+y-(-1y+3)), so:

4+y-(-1y+3)

determiningTheFunctionDomain
y-(-1y+3)+4

We get rid of parentheses

y+1y-3+4

We add all the numbers together, and all the variables

2y+1

Back to the equation:

-(2y+1)



We get rid of parentheses

-1(-3y+1)-2y-1+9=0

We add all the numbers together, and all the variables

-2y-1(-3y+1)+8=0

We move all terms containing y to the left, all other terms to the right

-2y-1(-3y+1)=-8

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