9-1(t+3)=-1+2(t-3)

Solution for 9-1(t+3)=-1+2(t-3) equation:

9-1(t+3)=-1+2(t-3)

We move all terms to the left:

9-1(t+3)-(-1+2(t-3))=0


We calculate terms in parentheses: -(-1+2(t-3)), so:

-1+2(t-3)

determiningTheFunctionDomain
2(t-3)-1

We multiply parentheses

2t-6-1

We add all the numbers together, and all the variables

2t-7

Back to the equation:

-(2t-7)


We get rid of parentheses

-1(t+3)-2t+7+9=0

We add all the numbers together, and all the variables

-2t-1(t+3)+16=0

We move all terms containing t to the left, all other terms to the right

-2t-1(t+3)=-16