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9-1/2y=5+4y
We move all terms to the left:
9-1/2y-(5+4y)=0
Domain of the equation: 2y!=0We add all the numbers together, and all the variables
y!=0/2
y!=0
y∈R
-1/2y-(4y+5)+9=0
We get rid of parentheses
-1/2y-4y-5+9=0
We multiply all the terms by the denominator
-4y*2y-5*2y+9*2y-1=0
Wy multiply elements
-8y^2-10y+18y-1=0
We add all the numbers together, and all the variables
-8y^2+8y-1=0
a = -8; b = 8; c = -1;
Δ = b2-4ac
Δ = 82-4·(-8)·(-1)
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{2}}{2*-8}=\frac{-8-4\sqrt{2}}{-16} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{2}}{2*-8}=\frac{-8+4\sqrt{2}}{-16} $
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