If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9-11x^2=3x
We move all terms to the left:
9-11x^2-(3x)=0
a = -11; b = -3; c = +9;
Δ = b2-4ac
Δ = -32-4·(-11)·9
Δ = 405
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{405}=\sqrt{81*5}=\sqrt{81}*\sqrt{5}=9\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-9\sqrt{5}}{2*-11}=\frac{3-9\sqrt{5}}{-22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+9\sqrt{5}}{2*-11}=\frac{3+9\sqrt{5}}{-22} $
| 36=6x+1x+7 | | 5x-7=-8x2 | | 7(4x75)=63 | | 70-4x=+4x | | -3(v-8)=-5v+36 | | 6/v=17/13 | | 10+-1x=4x | | 3+2(4+x)=-29-6x | | (10+x)/4(x=6) | | 4-r=-5r+16 | | 36+6v=15v | | n/4+3(n=12) | | n-7=14+8n | | 5^x=9(3^x) | | 21/4=7/8=49/x | | -2-4n+5n=-11+4n | | 2/3(6x+9)=1/3(6x-24) | | 2/9x+8=12 | | -102=6k | | 3*x-13=17 | | (4x/3)+12-2x=32 | | 10/b=1.000 | | 3(-2+4)-4x-2=20 | | 2^x2-5x+3=0 | | 4r^2+20+25=0 | | 225x+3=0 | | 8m-3m=6+6m | | 11x+2=72 | | 2b+1=b-6 | | 7/15x=49 | | 7/25x=49 | | x^2+15x-32=74 |