9-17k=2k2

Solution for 9-17k=2k2 equation:

9-17k=2k^2

We move all terms to the left:

9-17k-(2k^2)=0

determiningTheFunctionDomain
-2k^2-17k+9=0

a = -2; b = -17; c = +9;
Δ = b2-4ac
Δ = -172-4·(-2)·9
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-19}{2*-2}=\frac{-2}{-4}
=1/2
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+19}{2*-2}=\frac{36}{-4}
=-9
$