9-2(x+3)=4(x+5)-7

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Solution for 9-2(x+3)=4(x+5)-7 equation: 



9-2(x+3)=4(x+5)-7

We move all terms to the left:

9-2(x+3)-(4(x+5)-7)=0

We multiply parentheses

-2x-(4(x+5)-7)-6+9=0



We calculate terms in parentheses: -(4(x+5)-7), so:

4(x+5)-7

We multiply parentheses

4x+20-7

We add all the numbers together, and all the variables

4x+13

Back to the equation:

-(4x+13)



We add all the numbers together, and all the variables

-2x-(4x+13)+3=0

We get rid of parentheses

-2x-4x-13+3=0

We add all the numbers together, and all the variables

-6x-10=0

We move all terms containing x to the left, all other terms to the right

-6x=10

x=10/-6

x=-1+2/3

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