9-2(x+4)=3x-4(x+1)

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Solution for 9-2(x+4)=3x-4(x+1) equation: 



9-2(x+4)=3x-4(x+1)

We move all terms to the left:

9-2(x+4)-(3x-4(x+1))=0

We multiply parentheses

-2x-(3x-4(x+1))-8+9=0



We calculate terms in parentheses: -(3x-4(x+1)), so:

3x-4(x+1)

We multiply parentheses

3x-4x-4

We add all the numbers together, and all the variables

-1x-4

Back to the equation:

-(-1x-4)



We add all the numbers together, and all the variables

-2x-(-1x-4)+1=0

We get rid of parentheses

-2x+1x+4+1=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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