9-2(x-2)=4x-2(x-5)-3

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Solution for 9-2(x-2)=4x-2(x-5)-3 equation:



9-2(x-2)=4x-2(x-5)-3
We move all terms to the left:
9-2(x-2)-(4x-2(x-5)-3)=0
We multiply parentheses
-2x-(4x-2(x-5)-3)+4+9=0
We calculate terms in parentheses: -(4x-2(x-5)-3), so:
4x-2(x-5)-3
We multiply parentheses
4x-2x+10-3
We add all the numbers together, and all the variables
2x+7
Back to the equation:
-(2x+7)
We add all the numbers together, and all the variables
-2x-(2x+7)+13=0
We get rid of parentheses
-2x-2x-7+13=0
We add all the numbers together, and all the variables
-4x+6=0
We move all terms containing x to the left, all other terms to the right
-4x=-6
x=-6/-4
x=1+1/2

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