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9-2/3y=y
We move all terms to the left:
9-2/3y-(y)=0
Domain of the equation: 3y!=0We add all the numbers together, and all the variables
y!=0/3
y!=0
y∈R
-1y-2/3y+9=0
We multiply all the terms by the denominator
-1y*3y+9*3y-2=0
Wy multiply elements
-3y^2+27y-2=0
a = -3; b = 27; c = -2;
Δ = b2-4ac
Δ = 272-4·(-3)·(-2)
Δ = 705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{705}}{2*-3}=\frac{-27-\sqrt{705}}{-6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{705}}{2*-3}=\frac{-27+\sqrt{705}}{-6} $
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