9-2/b=5+4b

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Solution for 9-2/b=5+4b equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

9-(2/b) = 4*b+5 // - 4*b+5

9-(4*b)-(2/b)-5 = 0

9-4*b-2*b^-1-5 = 0

4*b^0-4*b^1-2*b^-1 = 0

(4*b^1-4*b^2-2*b^0)/(b^1) = 0 // * b^2

b^1*(4*b^1-4*b^2-2*b^0) = 0

b^1

4*b-4*b^2-2 = 0

4*b-4*b^2-2 = 0

DELTA = 4^2-(-4*(-2)*4)

DELTA = -16

DELTA < 0

b in { } 

b belongs to the empty set

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