9-20(3y-2)=27+5(4y-5)

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Solution for 9-20(3y-2)=27+5(4y-5) equation: 



9-20(3y-2)=27+5(4y-5)

We move all terms to the left:

9-20(3y-2)-(27+5(4y-5))=0

We multiply parentheses

-60y-(27+5(4y-5))+40+9=0



We calculate terms in parentheses: -(27+5(4y-5)), so:

27+5(4y-5)

determiningTheFunctionDomain
5(4y-5)+27

We multiply parentheses

20y-25+27

We add all the numbers together, and all the variables

20y+2

Back to the equation:

-(20y+2)



We add all the numbers together, and all the variables

-60y-(20y+2)+49=0

We get rid of parentheses

-60y-20y-2+49=0

We add all the numbers together, and all the variables

-80y+47=0

We move all terms containing y to the left, all other terms to the right

-80y=-47

y=-47/-80

y=47/80

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