9-2x(3-x)=5

Solution for 9-2x(3-x)=5 equation:

9-2x(3-x)=5

We move all terms to the left:

9-2x(3-x)-(5)=0

We add all the numbers together, and all the variables

-2x(-1x+3)+9-5=0

We add all the numbers together, and all the variables

-2x(-1x+3)+4=0

We multiply parentheses

2x^2-6x+4=0

a = 2; b = -6; c = +4;
Δ = b2-4ac
Δ = -62-4·2·4
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2}{2*2}=\frac{4}{4}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2}{2*2}=\frac{8}{4}
=2
$