9-2x(3-x)=5

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Solution for 9-2x(3-x)=5 equation:



9-2x(3-x)=5
We move all terms to the left:
9-2x(3-x)-(5)=0
We add all the numbers together, and all the variables
-2x(-1x+3)+9-5=0
We add all the numbers together, and all the variables
-2x(-1x+3)+4=0
We multiply parentheses
2x^2-6x+4=0
a = 2; b = -6; c = +4;
Δ = b2-4ac
Δ = -62-4·2·4
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2}{2*2}=\frac{4}{4} =1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2}{2*2}=\frac{8}{4} =2 $

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