9-3(x-4)=8+2(x+4)

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Solution for 9-3(x-4)=8+2(x+4) equation: 



9-3(x-4)=8+2(x+4)

We move all terms to the left:

9-3(x-4)-(8+2(x+4))=0

We multiply parentheses

-3x-(8+2(x+4))+12+9=0



We calculate terms in parentheses: -(8+2(x+4)), so:

8+2(x+4)

determiningTheFunctionDomain
2(x+4)+8

We multiply parentheses

2x+8+8

We add all the numbers together, and all the variables

2x+16

Back to the equation:

-(2x+16)



We add all the numbers together, and all the variables

-3x-(2x+16)+21=0

We get rid of parentheses

-3x-2x-16+21=0

We add all the numbers together, and all the variables

-5x+5=0

We move all terms containing x to the left, all other terms to the right

-5x=-5

x=-5/-5

x=1

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