9-4/2=2(y+2)/3

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Solution for 9-4/2=2(y+2)/3 equation: 



9-4/2=2(y+2)/3

We move all terms to the left:

9-4/2-(2(y+2)/3)=0

We add all the numbers together, and all the variables

-(2(y+2)/3)+7=0

We multiply all the terms by the denominator


-(2(y+2)+7*3)=0



We calculate terms in parentheses: -(2(y+2)+7*3), so:

2(y+2)+7*3

We add all the numbers together, and all the variables

2(y+2)+21

We multiply parentheses

2y+4+21

We add all the numbers together, and all the variables

2y+25

Back to the equation:

-(2y+25)



We get rid of parentheses

-2y-25=0

We move all terms containing y to the left, all other terms to the right

-2y=25

y=25/-2

y=-12+1/2

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