9-5(x-7)=10-(2x+1)

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Solution for 9-5(x-7)=10-(2x+1) equation: 



9-5(x-7)=10-(2x+1)

We move all terms to the left:

9-5(x-7)-(10-(2x+1))=0

We multiply parentheses

-5x-(10-(2x+1))+35+9=0



We calculate terms in parentheses: -(10-(2x+1)), so:

10-(2x+1)

determiningTheFunctionDomain
-(2x+1)+10

We get rid of parentheses

-2x-1+10

We add all the numbers together, and all the variables

-2x+9

Back to the equation:

-(-2x+9)



We add all the numbers together, and all the variables

-5x-(-2x+9)+44=0

We get rid of parentheses

-5x+2x-9+44=0

We add all the numbers together, and all the variables

-3x+35=0

We move all terms containing x to the left, all other terms to the right

-3x=-35

x=-35/-3

x=11+2/3

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