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9-5k=12-(6k+2)
We move all terms to the left:
9-5k-(12-(6k+2))=0
We calculate terms in parentheses: -(12-(6k+2)), so:We get rid of parentheses
12-(6k+2)
determiningTheFunctionDomain -(6k+2)+12
We get rid of parentheses
-6k-2+12
We add all the numbers together, and all the variables
-6k+10
Back to the equation:
-(-6k+10)
-5k+6k-10+9=0
We add all the numbers together, and all the variables
k-1=0
We move all terms containing k to the left, all other terms to the right
k=1
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