9-5z=z+12-(6z+3)

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Solution for 9-5z=z+12-(6z+3) equation: 


Simplifying
9 + -5z = z + 12 + -1(6z + 3)

Reorder the terms:
9 + -5z = z + 12 + -1(3 + 6z)
9 + -5z = z + 12 + (3 * -1 + 6z * -1)
9 + -5z = z + 12 + (-3 + -6z)

Reorder the terms:
9 + -5z = 12 + -3 + z + -6z

Combine like terms: 12 + -3 = 9
9 + -5z = 9 + z + -6z

Combine like terms: z + -6z = -5z
9 + -5z = 9 + -5z

Add '-9' to each side of the equation.
9 + -9 + -5z = 9 + -9 + -5z

Combine like terms: 9 + -9 = 0
0 + -5z = 9 + -9 + -5z
-5z = 9 + -9 + -5z

Combine like terms: 9 + -9 = 0
-5z = 0 + -5z
-5z = -5z

Add '5z' to each side of the equation.
-5z + 5z = -5z + 5z

Combine like terms: -5z + 5z = 0
0 = -5z + 5z

Combine like terms: -5z + 5z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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