9-6(2x-4)+9x=3(x-8)

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Solution for 9-6(2x-4)+9x=3(x-8) equation: 



9-6(2x-4)+9x=3(x-8)

We move all terms to the left:

9-6(2x-4)+9x-(3(x-8))=0

We add all the numbers together, and all the variables

9x-6(2x-4)-(3(x-8))+9=0

We multiply parentheses

9x-12x-(3(x-8))+24+9=0



We calculate terms in parentheses: -(3(x-8)), so:

3(x-8)

We multiply parentheses

3x-24

Back to the equation:

-(3x-24)



We add all the numbers together, and all the variables

-3x-(3x-24)+33=0

We get rid of parentheses

-3x-3x+24+33=0

We add all the numbers together, and all the variables

-6x+57=0

We move all terms containing x to the left, all other terms to the right

-6x=-57

x=-57/-6

x=9+1/2

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