9-6(2z+1)=-3(4z-1)

Solution for 9-6(2z+1)=-3(4z-1) equation:

Simplifying
9 + -6(2z + 1) = -3(4z + -1)

Reorder the terms:
9 + -6(1 + 2z) = -3(4z + -1)
9 + (1 * -6 + 2z * -6) = -3(4z + -1)
9 + (-6 + -12z) = -3(4z + -1)

Combine like terms: 9 + -6 = 3
3 + -12z = -3(4z + -1)

Reorder the terms:
3 + -12z = -3(-1 + 4z)
3 + -12z = (-1 * -3 + 4z * -3)
3 + -12z = (3 + -12z)

Add '-3' to each side of the equation.
3 + -3 + -12z = 3 + -3 + -12z

Combine like terms: 3 + -3 = 0
0 + -12z = 3 + -3 + -12z
-12z = 3 + -3 + -12z

Combine like terms: 3 + -3 = 0
-12z = 0 + -12z
-12z = -12z

Add '12z' to each side of the equation.
-12z + 12z = -12z + 12z

Combine like terms: -12z + 12z = 0
0 = -12z + 12z

Combine like terms: -12z + 12z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.