9-6(n-1)-(2n+5)=4-2(n+3)

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Solution for 9-6(n-1)-(2n+5)=4-2(n+3) equation: 



9-6(n-1)-(2n+5)=4-2(n+3)

We move all terms to the left:

9-6(n-1)-(2n+5)-(4-2(n+3))=0

We multiply parentheses

-6n-(2n+5)-(4-2(n+3))+6+9=0

We get rid of parentheses

-6n-2n-(4-2(n+3))-5+6+9=0



We calculate terms in parentheses: -(4-2(n+3)), so:

4-2(n+3)

determiningTheFunctionDomain
-2(n+3)+4

We multiply parentheses

-2n-6+4

We add all the numbers together, and all the variables

-2n-2

Back to the equation:

-(-2n-2)



We add all the numbers together, and all the variables

-8n-(-2n-2)+10=0

We get rid of parentheses

-8n+2n+2+10=0

We add all the numbers together, and all the variables

-6n+12=0

We move all terms containing n to the left, all other terms to the right

-6n=-12

n=-12/-6

n=+2

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