9-6(r+1)=2(r-4)+39

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Solution for 9-6(r+1)=2(r-4)+39 equation: 



9-6(r+1)=2(r-4)+39

We move all terms to the left:

9-6(r+1)-(2(r-4)+39)=0

We multiply parentheses

-6r-(2(r-4)+39)-6+9=0



We calculate terms in parentheses: -(2(r-4)+39), so:

2(r-4)+39

We multiply parentheses

2r-8+39

We add all the numbers together, and all the variables

2r+31

Back to the equation:

-(2r+31)



We add all the numbers together, and all the variables

-6r-(2r+31)+3=0

We get rid of parentheses

-6r-2r-31+3=0

We add all the numbers together, and all the variables

-8r-28=0

We move all terms containing r to the left, all other terms to the right

-8r=28

r=28/-8

r=-3+1/2

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