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9-6a-24a^2=0
a = -24; b = -6; c = +9;
Δ = b2-4ac
Δ = -62-4·(-24)·9
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-30}{2*-24}=\frac{-24}{-48} =1/2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+30}{2*-24}=\frac{36}{-48} =-3/4 $
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