9-7(8x-2)+4x=12x+3-2(4x-3)

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Solution for 9-7(8x-2)+4x=12x+3-2(4x-3) equation: 



9-7(8x-2)+4x=12x+3-2(4x-3)

We move all terms to the left:

9-7(8x-2)+4x-(12x+3-2(4x-3))=0

We add all the numbers together, and all the variables

4x-7(8x-2)-(12x+3-2(4x-3))+9=0

We multiply parentheses

4x-56x-(12x+3-2(4x-3))+14+9=0



We calculate terms in parentheses: -(12x+3-2(4x-3)), so:

12x+3-2(4x-3)

determiningTheFunctionDomain
12x-2(4x-3)+3

We multiply parentheses

12x-8x+6+3

We add all the numbers together, and all the variables

4x+9

Back to the equation:

-(4x+9)



We add all the numbers together, and all the variables

-52x-(4x+9)+23=0

We get rid of parentheses

-52x-4x-9+23=0

We add all the numbers together, and all the variables

-56x+14=0

We move all terms containing x to the left, all other terms to the right

-56x=-14

x=-14/-56

x=1/4

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