9-R/5=(5(r+2))/3

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Solution for 9-R/5=(5(r+2))/3 equation: 


x in (-oo:+oo)

9-(R/5) = (5*(r+2))/3 // - (5*(r+2))/3

9-((5*(r+2))/3)-(R/5) = 0

(-5/3)*(r+2)-(R/5)+9 = 0

9-5/3*(r+2)-R/5 = 0

(-5/3*5*(r+2))/5-R/5+(5*9)/5 = 0

5*9-5/3*5*(r+2)-R = 0

45-R-25/3*r-50/3 = 0

85/3-R-25/3*r = 0

(85/3-R-25/3*r)/5 = 0

(85/3-R-25/3*r)/5 = 0 // * 5

85/3-R-25/3*r = 0

x belongs to the empty set

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