If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9-x2/3=0
We multiply all the terms by the denominator
-x2+9*3=0
We add all the numbers together, and all the variables
-1x^2+27=0
a = -1; b = 0; c = +27;
Δ = b2-4ac
Δ = 02-4·(-1)·27
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{3}}{2*-1}=\frac{0-6\sqrt{3}}{-2} =-\frac{6\sqrt{3}}{-2} =-\frac{3\sqrt{3}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{3}}{2*-1}=\frac{0+6\sqrt{3}}{-2} =\frac{6\sqrt{3}}{-2} =\frac{3\sqrt{3}}{-1} $
| 7x-5=4x-2x | | 8k–4=20+4 | | 15= x2+37 | | 24=-2x+6 | | 110=10x-10 | | 3x+2=3(x+2 | | 84=2x+3 | | 33=4x+17 | | x+(x+25)+x*3=435 | | x+(x+25)+x53=435 | | 105=12x+21 | | (x+8)×4=21÷4 | | x+(x+25)+x3=435 | | -2-7=3x+4 | | 4(s+2)=20 | | (x+3)÷5-1/4=3/4 | | 12p+6=18 | | x/3–8=2 | | 5x+5=5x+5-2x+25 | | y/3+y-5/10=3y+5/5 | | 10x+3=5x-6 | | (3x)(-2-3x)-x=-3(-2-3) | | 1x+0.6=17.4 | | Q=78.53h | | -9u-14=4u+4-12u | | m7=-7 | | 5-j/12=1 | | 4(2x-3)+2x=18. | | x.04=2505.51 | | 7+7-10q=-9q-2 | | (3x-4)^2=400 | | 8k÷4=20÷4 |