9.8=2(12)/t2

Solution for 9.8=2(12)/t2 equation:

9.8=2(12)/t2

We move all terms to the left:

9.8-(2(12)/t2)=0


Domain of the equation: t2)!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

-(+212/t2)+9.8=0

We get rid of parentheses

-212/t2+9.8=0

We multiply all the terms by the denominator


(9.8)*t2-212=0

We multiply parentheses

9.8t^2-212=0

a = 9.8; b = 0; c = -212;
Δ = b2-4ac
Δ = 02-4·9.8·(-212)
Δ = 8310.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{8310.4}}{2*9.8}=\frac{0-\sqrt{8310.4}}{19.6}
=-\frac{\sqrt{}}{19.6}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{8310.4}}{2*9.8}=\frac{0+\sqrt{8310.4}}{19.6}
=\frac{\sqrt{}}{19.6}
$