9.9=2.6v2

Solution for 9.9=2.6v2 equation:

9.9=2.6v^2

We move all terms to the left:

9.9-(2.6v^2)=0

We get rid of parentheses

-2.6v^2+9.9=0

a = -2.6; b = 0; c = +9.9;
Δ = b2-4ac
Δ = 02-4·(-2.6)·9.9
Δ = 102.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{102.96}}{2*-2.6}=\frac{0-\sqrt{102.96}}{-5.2}
=-\frac{\sqrt{}}{-5.2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{102.96}}{2*-2.6}=\frac{0+\sqrt{102.96}}{-5.2}
=\frac{\sqrt{}}{-5.2}
$