9/-3x=12/x+10

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Solution for 9/-3x=12/x+10 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(9/(-3))*x = 12/x+10 // - 12/x+10

(9/(-3))*x-(12/x)-10 = 0

(9/(-3))*x-12*x^-1-10 = 0

-3*x^1-12*x^-1-10*x^0 = 0

(-3*x^2-10*x^1-12*x^0)/(x^1) = 0 // * x^2

x^1*(-3*x^2-10*x^1-12*x^0) = 0

x^1

-3*x^2-10*x-12 = 0

-3*x^2-10*x-12 = 0

DELTA = (-10)^2-(-12*(-3)*4)

DELTA = -44

DELTA < 0

x in { } 

x belongs to the empty set

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