9/1(2m-16)=1/3(2m+4)

Solution for 9/1(2m-16)=1/3(2m+4) equation:

9/1(2m-16)=1/3(2m+4)

We move all terms to the left:

9/1(2m-16)-(1/3(2m+4))=0


Domain of the equation: 1(2m-16)!=0

m∈R



Domain of the equation: 3(2m+4))!=0

m∈R


We calculate fractions


(27m2/(1(2m-16)*3(2m+4)))+(-m2/(1(2m-16)*3(2m+4)))=0


We calculate terms in parentheses: +(27m2/(1(2m-16)*3(2m+4))), so:

27m2/(1(2m-16)*3(2m+4))

We multiply all the terms by the denominator


27m2

We add all the numbers together, and all the variables

27m^2

Back to the equation:

+(27m^2)



We calculate terms in parentheses: +(-m2/(1(2m-16)*3(2m+4))), so:

-m2/(1(2m-16)*3(2m+4))

We multiply all the terms by the denominator


-m2

We add all the numbers together, and all the variables

-1m^2

Back to the equation:

+(-1m^2)


We add all the numbers together, and all the variables

27m^2+(-1m^2)=0

We get rid of parentheses

27m^2-1m^2=0

We add all the numbers together, and all the variables

26m^2=0

a = 26; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·26·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{52}=0$