9/10x+32=2/5(15-x)

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Solution for 9/10x+32=2/5(15-x) equation: 



9/10x+32=2/5(15-x)

We move all terms to the left:

9/10x+32-(2/5(15-x))=0



Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R





Domain of the equation: 5(15-x))!=0

x∈R



We add all the numbers together, and all the variables

9/10x-(2/5(-1x+15))+32=0

We calculate fractions


(45x(-)/(50x^2(-)+(-(2*10x)/(50x^2(-)+32=0

We can not solve this equation

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