9/2(8-x)+36=102-5/7(3x+24)

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Solution for 9/2(8-x)+36=102-5/7(3x+24) equation: 



9/2(8-x)+36=102-5/7(3x+24)

We move all terms to the left:

9/2(8-x)+36-(102-5/7(3x+24))=0



Domain of the equation: 2(8-x)!=0

x∈R





Domain of the equation: 7(3x+24))!=0

x∈R



We add all the numbers together, and all the variables

9/2(-1x+8)-(102-5/7(3x+24))+36=0

We calculate fractions


(63x3/(2(-1x+8)*7(3x+24)))+(-(-10x0)/(2(-1x+8)*7(3x+24)))+36=0



We calculate terms in parentheses: +(63x3/(2(-1x+8)*7(3x+24))), so:

63x3/(2(-1x+8)*7(3x+24))

We multiply all the terms by the denominator


63x3

We add all the numbers together, and all the variables

63x^3

We do not support expression: x^3

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