9/2(g+3)=1/2-g

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Solution for 9/2(g+3)=1/2-g equation: 



9/2(g+3)=1/2-g

We move all terms to the left:

9/2(g+3)-(1/2-g)=0



Domain of the equation: 2(g+3)!=0

g∈R





Domain of the equation: 2-g)!=0

We move all terms containing g to the left, all other terms to the right

-g)!=-2

g!=-2/1

g!=-2

g∈R



We add all the numbers together, and all the variables

9/2(g+3)-(-1g+1/2)=0

We get rid of parentheses

9/2(g+3)+1g-1/2=0

We calculate fractions


g=0

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