9/2(t-3)=27

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Solution for 9/2(t-3)=27 equation:



9/2(t-3)=27
We move all terms to the left:
9/2(t-3)-(27)=0
Domain of the equation: 2(t-3)!=0
t∈R
We multiply all the terms by the denominator
-27*2(t-3)+9=0
Wy multiply elements
-54t(t+9=0

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